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01_grundlagen/uebungen/u44_quersumme.html
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53
01_grundlagen/uebungen/u44_quersumme.html
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<!doctype html>
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<html lang="de">
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<head>
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<meta charset="UTF-8" />
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<meta name="viewport" content="width=device-width, initial-scale=1.0" />
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<title>Übung 44: Quersumme berechnen</title>
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<link href="https://cdn.jsdelivr.net/npm/bootstrap@5.3.8/dist/css/bootstrap.min.css" rel="stylesheet" />
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</head>
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<body>
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<main>
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<div class="container py-5">
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<div class="alert alert-primary">
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<h1>Übung 44: Quersumme berechnen</h1>
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<p>
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Schreibe eine Funktion digitSum, die die Quersumme einer übergebenen Zahl zurückgibt.
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<strong>Hinweis:</strong> Die Quersumme ist die Summe aller Ziffern einer Zahl. <br /><strong>Tipp:</strong>
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Verwenden Sie split('').
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</p>
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<div class="output alert alert-secondary my-3"></div>
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</div>
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</div>
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</main>
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<script>
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'use strict';
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const outputEl = document.querySelector('.output');
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const number = 4566;
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const getDigitSum = (n) => {
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// n in ein array umwandeln
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const digitAr = String(n).split(''); // (n).toString().split('')
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// => z.B. ['4','2','4','2']
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// Die quersumme berechnen und zurückgeben
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return digitAr.reduce((digit1, digit2) => Number(digit1) + Number(digit2), 0);
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};
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const getDigitSum1 = (n) => {
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return String(n) // => '4242'
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.split('') // => ['4','2','4','2']
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.map((str) => Number(str)) // => .map(Number) [4,2,4,2]
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.reduce((sum, n) => sum + n, 0); //=> 12
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};
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console.log(getDigitSum(4242)); //=> 12
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console.log(getDigitSum('13')); //=> 4
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console.log(getDigitSum(134)); //=> 8
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outputEl.textContent = `Die Quersumme von ${number} ist: ${getDigitSum(number)}!`;
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//========
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</script>
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</body>
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</html>
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